How to solve gas law problems?
Robert Bethell asked:
How do I solve these problems?
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How do I solve these problems?
1. a 2.5 L container of nitrogen had a pressure of 3.2 atm. What volume would be necessary to decrease the pressure to 760 mm Hg?
2. Ammonia gas occupies a volume of 450mL at a pressure of 720 torr. What volume will it occupy at standard pressure?
3. A 175mL sample of neon had its pressure chang from 85kPa to 1.50×10^5 Pa/ What is its new volume in liters?
August 25th, 2010 at 4:04 am
1. a 2.5 L container of nitrogen had a pressure of 3.2 atm. What volume would be necessary to decrease the pressure to 760 mm Hg?
formula: P1V1=P2V2
step 1: id values, plug into eqn and solve
step 2: check ans
P1=3.2 atm P2= 1 atm
V1=2.5 L V2= x
V2=P1V1/P2= 3.2 atm x 2.5 L/1 atm= 8 L
for the other problems they are work out in the same way. good luck. geek…..
August 27th, 2010 at 3:07 am
Use this formula
Pressure1 * Volume 1 = Pressure 2 * Volume 2
1. a (2.5 L = V1)…container of nitrogen had a pressure of (3.2 atm = P1)…. What volume would be necessary to decrease the pressure to 760 mm Hg? 760 mm =
(1 atm. pressure = P2)
Pressure1 * Volume 1 = Pressure 2 * Volume 2
2. Ammonia gas occupies a volume of (450mL = V1) at a pressure of (720 torr = P1). What volume will it occupy at standard pressure? Standard pressure =
(760 torr = P2)
Pressure1 * Volume 1 = Pressure 2 * Volume 2
720 * 450 = 760 * V2
V2 = (720 * 450) ÷ 760
V2 = 426 torr
3. A (75mL = V1) sample of neon had its pressure change from
(85kPa = P1)to (1.50×10^5 Pa = P2)/ What is its new volume in liters?
1.50×10^5 Pa = (P2 = 150 kPa)
Pressure1 * Volume 1 = Pressure 2 * Volume 2
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Thanks for the opportunity to be of help electron1
August 29th, 2010 at 1:06 am
All are based on Boyle’s Law: “At constant Temperature, The Volume of a mass of gas is Inversely Proportional to its Absolute Pressure”:
Pressure Increase Volume Decrease in Proportion. P1V1 = P2V2.
1…3.2atm x 2.5L = 760mmHg (= 1.0atm) x V2.
V2 (New volume) = 8 / 1 = 8.0 L.
2…720 torr x 450mL = 760 torr x V2.
V2 (New volume) = 426.3mL.
3…1.5 x 10^5 = 150,000 Pa = 150kPa
85kPa x175mL = 150kPa x V2.
V2 (New volume) = 14,875 / 150 = 99.2mL. Norrie